Ad sense

Wednesday, December 17, 2008

Quantitative Test

Quantitative Aptitude

Q-1 Find xy in 3344xy if it divisible by 4?
(a) 15 (b) 48
(c) 26 (d None
Q-2 x = 42/3 85/2 / 43/5 find x
(a) 253/4 (b) 2/8
(c) 253/6/ 26/5 (d) None
Q-3 If -2 < -1 , then if it is multiplied by -5, then it become
(a) 10 <> 5
(c) 10 = 5 (d) None
Q-4 If side of equilateral triangle is 4cm, then what will be its area?
(a) 4cm2 (b) 4Ö3 cm2
(c) 45 cm2 (d) none
Q-5 If 10n = 1000 find n
(a) 2 (b) 3
(c) 4 (d) 8
Q-6 If there are 10 players, then find the No. of ways by which we can choose 3 Player
(a) 110 (b) 120
(c) 130 (d) 140
Q-7 which in not correct one in 3348, 3456, 3468, 3416
(a) 3468 (b) 3348
(c) 3456 (d) None
Q-8 36, 41, 43. 48. 53 , find different one
(a) 41 (b) 43
(c) 53 (d) None
Q-9 Find x2 + y2 + 2xy +3 if x= 3+ √2 & y = 3 - √2
(a) 40 (b) 39
(c) 38 (d) None
Q-10 1/√2 = ?
(a) √2/2 (b) √3
(c) 2 (d) None
Q-11 Find x if (x/25) (x/25) = ?
(a) 26 (b) 25
(c) 90 (d) 135
Q-12 HCF of (21,25) is
(a) 1 (b) 2
(c) 3 (d) 5
Q-13 What will be value of x if arithmetic mean of 2,5,9, ×6,8 is 10
(a) 20 (b) 30
(c) 40 (d) 90
Q-14 What will be a m of 1,2,3,4,……10
(a) 5.4 (b) 5.5.
(c) 5.9. (d) None
Q-15 Find eq. of spare thought circle x2 + y2 + z2 = 5, x+ y +z = 0,which passes through O
(0,0,0)
(a) 2x2 + 2y2 + 2z2 - x - y – z = 0
(b) x + y + z = 0
(c) 2x2 + 2y2 + 2z2 + x +y = 0
(d) None
Q-16 HCF of 23×32×52, 2×31 ×54 , 23×32 ×41 is
(a) 7 (b) 6
(c) 8 (d) 9
Q-17 2 is only……prime no?
(a) Even (b) odd
(c) Integer (d) None
Q-18 13692 is always divisibly by
(a) 3 (b) 2
(c) 5 (d) 9
Q-19 3312 is divisible by
(a) 3 (b) 12
(c) 6 (d) 8
Q-20 √×/3= 4 find
(a) 145 (b) 144
(c) 118 (d) None
Q-21 Find average of 2,6,8,10,12
(a) 9 (b) 8
(c) 9 (d) 10
Q-22 which comes next is 2, 12, 22, 32,
(a) 52 (b) 42
(c) 36 (d) 48
Q-23 10% of 20% of 10 is
(a) 1/6 (b) 1/5
(c) 1/8 (d) 1/9
Q-24 (0.008) × 1000+ 10
(a) 18 (b) 20
(c) 10 (d) 19
Q-25 1310 + 1378 -2600
(a) 88 (b) 98
(c) 198 (d) None


Answers:
1(b) Here we select 48 because if any no. is divisible by 4 then last two digit are divisible by 4
2(c) x = (22) 2/3 (23) 5/2 / (22) 3/5 = 24/3 215/2 / 26/5= 24/3+ 5/2
28+45/6 / 26/5 = 253/6 / 24/5
3(b) – 2 < –1 , 10 < 5
4(b) Area = (√3/4) (4)2= (√ 3) 4 x 4√3cm2
5(b) 10n = 103 , n = 3
6(b) C ( 10,3) = 10/(10-3)! 3! = 10.9.5.7!/7!.3! = 10.9.5/3.2.= 120
7(a) Here except 3468, other are divisible by 4
8(c) Here 53 in wrong because by sequence order we have to add 3 not 5
9(b) x2+ y2 + 2xy + 3= (3+ √2)2 + (3 - √2)2 + 2(3+ √2) (3- √2) + 3 = (9 + 2+ 6√2) + (9+2 - 6√2) + 2(9-2) +3
22+ 14+ 3 = 39
10(a) 1/√2 = √2/√2√2 = √2/2
11(b) x2 /25 . x2 /25 = 625, x= 25
12(a)
13(b) 2+5+9+x+6+8 /6 =10
30+x/6= 10 , 30 +x = 60
x = 30
14(b) a. m = 1+2+3+……+10/10 ,
10(10+1)/2/10 , 11/2 , 5.5.
15(a) Eq. of sphere though circle (x2 + y2 + z2– 5) + k(x + y + 2 - 10) = 0 when it passes through the (0,0,0,) (o+o+o-5)+k(0+0+0-10)= 0 , 5- 10k = 0 , – 10k = +5 put in 1 k = -1/2
(x2 +y2 +z2 -5) - ½ (x + y + 2 - 10) = 0 , 2x2 +2y2 +2z2 -10 - x- y- z +10 = 0
16(b) HCF is 2×31 = 6
17(a)
18b)
19a)
20(b) √x = 12, x = 144
21(b) Ave. = 21+6+8+12+12/5 , 40/5= 8
22(b)
23(b) 10/100 ×20/100× 10 = 1/5
24(a) 8/1000 × 1000 + 10 = 8+10 = 18
25(a) 2688 - 2600 = 88

No comments:

Post a Comment

Ads

.

.